Question #260393

A perpetuity paying 1.000$ at the end of each month is replaced with an annuity paying X$ each month for 10 years. Calculate X if j4 = 7%


If the annuity paid 2.500$ at the end of each month, how long would the annuity last and what would be the size of the final, smaller payment?


1
Expert's answer
2021-11-08T06:14:38-0500

Solution:

j4=7%

i = 7/4 % = 1.75% p.a = 0.0175

PV of perpetuity =Amount of continuous cash paymentInterest rate or yield=\dfrac{\text{Amount of continuous cash payment}}{\text{Interest rate or yield}}

=$10.0175=$5717=\dfrac{\$ 1}{0.0175}=\$ 57\dfrac17

PV of annuity =P[1(1+r)nr]=P[\dfrac{1-(1+r)^{-n}}{r}]

Given, P=$X,r=0.0175,n=10P=\$X, r=0.0175,n=10

So, PV of annuity =X[1(1+0.0175)100.0175]=9.10122X=X[\dfrac{1-(1+0.0175)^{-10}}{0.0175}]=9.10122X

Now, 9.10122X=57179.10122X=57\dfrac 17

X=$6.278\Rightarrow X=\$6.278


Now, P=$2.5,n=?P=\$2.5,n=?

PV of annuity =P[1(1+r)nr]=P[\dfrac{1-(1+r)^{-n}}{r}]

PV=$5717PV=\$ 57\dfrac17

5717=2.5[1(1+0.0175)n0.0175]0.4=1(1+0.0175)n(1.0175)n=0.6nlog1.0175=log0.6n=29.443057\dfrac17=2.5[\dfrac{1-(1+0.0175)^{-n}}{0.0175}] \\\Rightarrow 0.4=1-(1+0.0175)^{-n} \\\Rightarrow (1.0175)^{-n}=0.6 \\\Rightarrow -n\log 1.0175=\log 0.6 \\\Rightarrow n=29.44\approx 30


Now, for n=30,

PV=2.5[1(1+0.0175)300.0175]=57.964PV=2.5[\dfrac{1-(1+0.0175)^{-30}}{0.0175}]=57.964

Final payment will be =57.9645717=$0.823=57.964-57\dfrac17=\$0.823


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