Amount needed to be saved, A is 10000
Interest rate, r is 0.12% compounded monthly
Time, t is 3 years
Let the amount that needs to be deposited be P
So;
A"=" P"[" 1"+\\frac{r}{n}]^{nt}"
P"[" 1"+\\frac{0.12}{1200}]^{12}\\times^{3}" "=" 10000
P"[" 1"+0.0001]^{36}" "=" 10000
1.0001"^{36}" P"=" 10000
1.003606P"=" 10000
P is 9964.069
Answer is Php9964.06
Comments
Leave a comment