Answer to Question #241157 in Financial Math for adelfa molina

Question #241157

Aaron Abbot invested P100,000 at 12% interest, compounded semi-annually, for 3 years. What is the future value?


1
Expert's answer
2021-09-24T13:15:29-0400

I=P(1+rn)ntI = {P(1+\frac{r}{n})}^{nt}

Year1=100,000  (1+0.122)(21)=112360Year1 = {100,000\ *\ (1+\frac{0.12}{2})}^{(2*1)} = 112360


Year2=112,360  (1+0.122)(21)=126,247.70Year2 = {112,360\ *\ (1+\frac{0.12}{2})}^{(2*1)} = 126,247.70


Year3=126,247.70  (1+0.122)(21)=141,851.91Year3 = {126,247.70\ *\ (1+\frac{0.12}{2})}^{(2*1)} = 141,851.91


1st year interest will be $12,3601st\ year\ interest \ will\ be\ \$12,360


2nd year interest will be $13,887.702nd\ year\ interest \ will\ be\ \$13,887.70


3rd year interest will be $15,604.213rd\ year\ interest \ will\ be\ \$15,604.21


the total interest earned will be $41,851.91 after 3yearsthe \ total\ interest\ earned\ will\ be \ \$ 41,851.91\ after\ 3years


the compound amount earned will be $141,851.91 after 3yearsthe \ compound\ amount \ earned\ will\ be \ \$ 141,851.91\ after\ 3years




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