Find the lump sum deposit which will give $9,430 in 10 years in an account paying 1.24% compounded monthly.
First, convert R as a percent to r as a decimal
"r = \\frac{1.24}{100}\\\\\n\nr = 0.0124" rate per year,
"A = P(1 +\\frac{ r}{n})^{nt}"
A = Accrued amount,P is the Principal ,r is annual nominal interest rate as a decimal,n is number of compounding periods per unit of time and t time in decimal years
"9430 = P\\times(1 + \\frac{0.0124}{12})^{(12)(10)}\\\\\n\n9430 = P\\times(1.001033333)^{(120)}\\\\\n9430 =1.131943399P\\\\P=\\frac{9430} {1.131943399}\\\\P=\\$8330.81"
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