Monthly payment×(Number of months−-− Loan) =Interest
=>Monthly payment×n−-− Loan=328.85
=>Loan×(R12)(1−1(1+R12)n)×n−Loan=328.85Loan×\frac {(\frac {R} {12} )} {(1-{1} {(1+\frac {R} {12} )^n)}} ×n-Loan=328.85Loan×(1−1(1+12R)n)(12R)×n−Loan=328.85
=P×(9.512)(1−1(1+9.512)11)×11−1=328.85=P×\frac {(\frac {9.5} {12} )} {(1-{1} {(1+\frac {9.5} {12} )^{11} )}} ×11-1=328.85=P×(1−1(1+129.5)11)(129.5)×11−1=328.85
Principal Amount =6833.36
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