Question #207725

Derek the contractor took out a loan to purchase lumber forone of his projects. He ended up 5328.85 in interestover an 11 month period it theaterestrate on the loan was9.5% how much dhe end up spending on lumber?What was the principal amount of the loan?

Expert's answer

Monthly payment×(Number of months−- Loan) =Interest


=>Monthly payment×n−- Loan=328.85


=>Loan×(R12)(1−1(1+R12)n)×n−Loan=328.85Loan×\frac {(\frac {R} {12} )} {(1-{1} {(1+\frac {R} {12} )^n)}} ×n-Loan=328.85


=P×(9.512)(1−1(1+9.512)11)×11−1=328.85=P×\frac {(\frac {9.5} {12} )} {(1-{1} {(1+\frac {9.5} {12} )^{11} )}} ×11-1=328.85


Principal Amount =6833.36


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