h(0,t)=0.02+0.005(1)
=0.02+0.005
Therefore, V(0,1) = 0.025.
h(0,t)=0.02+0.005(2)
= 0.02+0.01
Therefore, v(0,2) =0.3
h(0,t)=0.02+0.005(3)
=0.02+0.015
Therefore, v(0,3)=0.035.
h(0,t)=0.02+0.005(1)
=0.02+0.005
Therefore, m(0,1) = 0.025.
h(0,t)=0.02+0.005(3)
0.02+0.015
Therefore, m(0,3)=0.035.
B) the no arbitrage price for a 3year period and notional of 200.
A(0,3)*200
h(0,t)={0.02+0.005(3)}*200
(0.02+0.015)*200
0.035*200
=7
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