Percy deposits R100 into a bank account earning interest at an interest rate of 18% per annum, compounded monthly. The time (in months) that it will take the account to accumulate to R20 000 is given by
[1] n = ln[200(1,015)] 0,015 .
[2] n = ln[200(0,015) + 1] ln(1 + 0,015) .
[3] n = ln[200(1,015) + 1] − ln(1,015).
[4] n = ln[200(0,015) − 1] ln(1 + 1,015) .
[5] none of the above.
A =R 20,000
R = (18/12 )%
= 1.5 %
A = p(1+r/100)n
20,000 = 100(1+0.015)n
(20,000/100) = 1.015n
200 = 1.015 n
Introducing indices,
In 200 = n In 1.015 therefore,
n = ln[200(0,015) − 1] ln(1 + 1,015)
Choice 4 is correct
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