An amount of R3 450 earns simple interest and accumulates to R5623, 50 after seven years. Had the yearly interest rate been 2% more, how much interest would he have accumulated in seven years
5623.50−3450=3450×r1×72173.5=24150×r1r1=2173.524150=0.09=9 %r2=r1+2=11 %=0.11X−3450=3450×0.11×7X−3450=2656.5X=6106.5Interest=6106.5−3450=2656.55623.50 -3450 = 3450 \times r_1 \times 7 \\ 2173.5 = 24150 \times r_1 \\ r_1 = \frac{2173.5}{24150} = 0.09 = 9 \; \% \\ r_2 = r_1 + 2 = 11 \; \% = 0.11 \\ X-3450 = 3450 \times 0.11 \times 7 \\ X-3450 = 2656.5 \\ X = 6106.5 \\ Interest = 6106.5 -3450 = 2656.55623.50−3450=3450×r1×72173.5=24150×r1r1=241502173.5=0.09=9%r2=r1+2=11%=0.11X−3450=3450×0.11×7X−3450=2656.5X=6106.5Interest=6106.5−3450=2656.5
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