An amount of R4 317,26 was borrowed on 5 May at a simple interest rate of 15% per year. The loan will be worth R4 500 on
[1] 16 August.
[2] 12 August.
[3] 21 August.
[4] 9 October.
[5] none of the above.
simple interest rate",S=P(1+rt)"
"t=5may" till 16 Aug
date value =228-125=103days
"t=103\/365"
"S=p(1+rt)=4317,26(1+15\/100\\times 103\/365)=R4500"
Therefore, the loan will be worth R4 500 on 16 August. The answer is [1] 16 August
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