Lesiba invests an amount of money in an a ount earning 13,88% interest per year, ompounded weekly. After ve years, this amount has a umulated to R50 000. The amount that was invested initially is
[1] R26 105,54.
[2] R15 300,00.
[3] R29 515,94.
[4] R25 001,79.
[5] R34 700,00.
P=principal or amount invested initially,t= time in years
A = amount , r = the interest rate per time period, and n = the number of time periods
t=5×52=260
"P=\\frac{A}{(1+\\frac{r}{n})^{t\u00d7n}}"
The amount that was invested initially is:
"P = 50,000\/(1 + 0.1388\/52)^{260} = R25,001.79."
So, the correct answer is 4.
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