Question #192445

Lesiba invests an amount of money in an a ount earning 13,88% interest per year, ompounded weekly. After ve years, this amount has a umulated to R50 000. The amount that was invested initially is

[1] R26 105,54.

[2] R15 300,00.

[3] R29 515,94.

[4] R25 001,79.

[5] R34 700,00.


1
Expert's answer
2021-06-15T09:17:31-0400

P=principal or amount invested initially,t= time in years

A = amount , r = the interest rate per time period, and n = the number of time periods

t=5×52=260

P=A(1+rn)t×nP=\frac{A}{(1+\frac{r}{n})^{t×n}}

The amount that was invested initially is: 

P=50,000/(1+0.1388/52)260=R25,001.79.P = 50,000/(1 + 0.1388/52)^{260} = R25,001.79.

So, the correct answer is 4.



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