Question #191493

Find the present value of a series of investment of  $1  at the beginning of each year for 15 years with effective interest rate of 13.5% p.a.


Expert's answer

Solution:

Given, p=$1,r=13.5% p.a.=0.135,n=15 yearsp=\$1,r=13.5\%\ p.a.=0.135, n=15\ years

So, present value,PV=p[1−(1+r)−nr]PV=p[\dfrac{1-(1+r)^{-n}}{r}]

=1[1−(1+0.135)−150.135]=$6.298926≈$6.3=1[\dfrac{1-(1+0.135)^{-15}}{0.135}]=\$6.298926\approx\$6.3


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