Find the present value of a series of investment of $1 at the beginning of each year for 15 years with effective interest rate of 13.5% p.a.
Solution:
Given, "p=\\$1,r=13.5\\%\\ p.a.=0.135, n=15\\ years"
So, present value,"PV=p[\\dfrac{1-(1+r)^{-n}}{r}]"
"=1[\\dfrac{1-(1+0.135)^{-15}}{0.135}]=\\$6.298926\\approx\\$6.3"
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