Tony makes deposits of $320 monthly (at the end of each month) into an account that pays 1.8% interest compounded monthly.
How much interest will he have earned after 3 years?
"A=p(1+\\frac{r}{(12)(100)})^{12\\times n}=320(1+\\frac{1.8}{(12)(100)})^{12\\times 3}=320\\times1.0554=\\$337.728"
"I=A-P=337.728-320=\\$17.728"
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