Answer to Question #164740 in Financial Math for sally

Question #164740

Alyce operates a factory that manufactures pencil boxes which she sells to stationery store.


Additional information:

Annual demand is 1 million pencil boxes per year

Setup cost is $5000 per batch

Holding cost is $3 per year for each pencil boxes

Maximum production capacity is 2 million pencil boxes per year


Currently, pencil boxes are manufactured in 10 batches.

1a) Find the optimum production quantity that Alyce should produce to minimize her costs.

  b) Calculate the current annual holding cost and setup cost. 

  c) Draw a diagram showing stock level for the first batch, assume 1 year has 250 working

      days 




1
Expert's answer
2021-02-22T11:33:51-0500

Given,

Set up cost, Cs=C_s= 5000$

Holding cost, Ch=3C_h=3 $

Maximum capacity, P=2,000,000P=2,000,000

Annual producing capacity, D=1,000,000D=1,000,000


Solution A: Optimum Production Quantity


Economic Batch Quantity

=(2×Cs×D)Ch(1DP)= \sqrt{ \dfrac{(2 \times C_s \times D)}{C_h(1 - \dfrac{D}{P})}}


=(2×5000×1,000,000)3(1(1,000,000)2,000,000))= \sqrt{ \dfrac{(2 × 5000× 1,000,000)}{3 (1-\dfrac{(1,000,000)}{2,000,000)})}}


=(10,000,000,000)1.5= \sqrt{ \dfrac{(10,000,000,000)}{1.5}}


=6,666,666,666= \sqrt{6,666,666,666}


=81,650= 81,650 units


Alyce should manufacture bottles in batches of 81,650units.81,650 \text{units}.


Solution B: Current Costs


Batch Quantity = Annual Demand ÷ Number of batches


 =1,000,000÷10=100,000units= 1,000,000 ÷ 10 = 100,000 units


Annual Holding Cost =(Batch Quantity2)×Ch×(1DP)\dfrac{\text{(Batch Quantity}}{2}) × C_h × (1- \dfrac{D}{P})


 =(100,000)2×3×(1(1,000,000)2,000,000)= (\dfrac{100,000)}{2} × 3 × (1-\dfrac{(1,000,000)}{2,000,000)}


=75,000= 75,000 $


Setup Cost = Number of setups × setup cost


 =10×5000=50,000= 10 × 5000 = 50,000 $


Total Current Cost =(75,000+50,000)=125,000= (75,000+ 50,000) = 125,000 $


Solution C: Savings from EBQ


Annual Holding Cost:


 =(Batch Quantity2)×Ch×(1DP)= \dfrac{\text{(Batch Quantity}}{2}) × Ch × (1- \dfrac{D}{P})


 =(81,650)2×3×(1(1,000,000)2,000,000)= \dfrac{(81,650)}{2} × 3 × (1-\dfrac{(1,000,000)}{2,000,000})


=61,238= 61,238 $


Setup Cost:


Number of batches =1,000,000÷81,650=12.2475= 1,000,000 ÷ 81,650 = 12.2475


Setup Cost = Number of batches × Cost of setup


=12.2475×5000=61,23(B)= 12.2475 × 5000 = 61,23 (B)


Total Cost (EBQ) =(A)+(B)=122,476(C)= (A) + (B) = 122,476 (C)


Total Current Cost =125,000(D)= 125,000 (D)


Savings =(D)(C)=2,524= (D) - (C) = 2,524 $

With increasing time the stock level of pencil boxes increasing. Stock diagram is given by






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