If the interest is calculated yearly, then:
"100,000\u00d71.0625^x = 150,000,"
"\\log(1. 0625) 1.5 = 6.69"
years.
If the interest is paid monthly, then:
"100,000\u00d7(1 + 0.0625\/12)^{12x} = 150,000,"
"\\log(1.0052) 1.5\/12 = 6.51" years.
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