Question

Find the measure of the following .in circle V.mAVE=90° mIVD=(2x)° and mEVS=(6X-28)°

Answer 1

$V.mAVE\degree+m/VD\degree+mEVS\degree=180\degree$

$90\degree+(2X)\degree+(6X-28)\degree=180\degree$

$2X+6X=180-90+28$

$8X=62$

$X=7.75\degree$

$\therefore m/VD=2\times7.75$

$=15.5\degree$

$mEVS=(6\times7.75)-28$

$=18.5\degree$