c=S0×N(d1)−K×N(d2)×DFd1=σ×t0.5ln(KS0)+(r+2σ2)×t
d2=d1−σ×t0.5
DF=e−r×t
S0=100
K=200
σ=0.1
r=0.08, 0.0067 years
t=2, 0.167 years
DF=e−0.0067×0.167=0.999
d1=0.1×0.1670.5ln(200100)+(0.0067+20.12)×0.167=−0.6455
d2=−0.6455−0.1×0.1670.5=0.6863
c=100×N(−0.6455)−200×N(−0.6863)×0.999=−23.27
K=320
DF=e−0.0067×0.167=0.999
d1=0.1×0.1670.5ln(320100)+(0.0067+20.12)×0.167=−1.1155
d2=−1.1155−0.1×0.1670.5=−1.1563
c=100×N(−1.1155)−320×N(−1.1563)×0.999=−26.33
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