PV=2500
at the beginning of the year:
"PV=C[\\frac{1-(1+r)^{-n}}{r}]\\times(1+r)"
"2500=C[\\frac{1-(1+0.0776)^{-6}}{0.0776}]\\times(1+0.0776)"
"C=\\frac{2500}{5.01806503}=498.2"
at the end of each year:
"PV=C[\\frac{1-(1+r)^{-n}}{r}]"
"2500=C[\\frac{1-(1+0.0776)^{-6}}{0.0776}]"
"C=\\frac{2500}{4.65673159}=536.86"
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