"A=P(1+\\frac{r}{100})^n"
"3P=P(1+\\frac{4}{400})^{4n}"
Dividing by P we obtain,
"3=(1.01)^{4n}"
Taking the logarithm of both sides
"log3=4nlog1.01"
This implies that
"4n=\\frac{log3}{log1.01}"
"n=\\frac{log3}{4log1.01}"
"n=27. 60years"
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