k=6%, n=3, S0=$12000.k=6\%,~n=3,~S_0=\$12000.k=6%, n=3, S0=$12000.
S=S0(1+k12⋅100%)n==$12000⋅1.0053=$12180.90S=S_0(1+\frac{k}{12\cdot100\%})^n=\\=\$12000\cdot1.005^3=\$12180.90S=S0(1+12⋅100%k)n==$12000⋅1.0053=$12180.90 .