Let the term be 3 years, than we solved by formula:
FV=A×(1+i)n−1iFV=A\times\frac{(1+i)^n-1}{i}FV=A×i(1+i)n−1
i=0.06312=0.00525i=\frac{0.063}{12}=0.00525i=120.063=0.00525
n=3∗12=36n=3*12=36n=3∗12=36
FV=A×(1+i)n−1i=1848×(1+0.00525)36−10.00525=73020.24FV=A\times\frac{(1+i)^n-1}{i}=1848\times\frac{(1+0.00525)^{36}-1}{0.00525}=73020.24FV=A×i(1+i)n−1=1848×0.00525(1+0.00525)36−1=73020.24
interest
73020.24−1848×36=73020.24−66528=6492.2473020.24-1848\times36=73020.24-66528=6492.2473020.24−1848×36=73020.24−66528=6492.24
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