We will assume that the annual rate is i. Then we have:
500((1+i)51+(1+i)61+..+(1+i)201)=3000 .
we go to step two where we obtain:
(1+i)55001−(1+i)1(1−(1+i)161)=3000
From it we receive:
((1+i)51−(1+i)211)=6(1−(1+i)1)
Solving the latter numerically, we obtain:
(1+i)1=0.91903
From the latter we obtain i:
i≈0.0881. Which is rounded off to 4 decimal places
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