solution
number of years (n) between 1980 and 2011
n=2011−1980=31years Inflation rate (r) =3.3% per year
Let X be the salary in 1980. The salary equivalent in 2011 is given by:
X∗(1+r)n Therefore
X∗(1+0.033)31=51,000
X=(1+0.033)3151,000
=18,640.61
answer: 1980 salary would be $18,640.61
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