Valueofbond=(1−(1+r2)2n)r2Value of bond= (1-(1+ \frac {r}{2})^{2n})\frac{r}{2}Valueofbond=(1−(1+2r)2n)2r +(Facevalue(1=r2)2n)(Face value (1=\frac {r}{2})^{2n})(Facevalue(1=2r)2n)
Value of bond=100000(1−(1+0.05)40.05)+(100000(1+0.05)4)100000(\frac{1-(1+0.05)^4}{0.05})+(100000(1+0.05)^4)100000(0.051−(1+0.05)4)+(100000(1+0.05)4)
=100000(−4.31012)+100000(1.215506)=100000(-4.31012)+100000(1.215506)=100000(−4.31012)+100000(1.215506)
=−431012+121550.62= -431012 + 121550.62=−431012+121550.62
R309462R309462R309462 decrease
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