Optimal oder quantity = "\\sqrt{2\u00d7d\u00d7co\\over ch} \n\n\u200b"
Where d demand in this case its what the company uses
Co is the carrying cost
Ch is holding cost
"\\sqrt{2\u00d76500\u00d728\\over3} \n\n\u200b\t\n \n\u200b"
The optimal quantity is ∴ 348.32
The total cost is therefore
Odering cost + carrying cost +holding cost +purchasing cost"( \n\n(65000\/348)\n\u200b\t\n \u00d728)+ \n\n348\/2\n\u200b\t\n ( \n\n(6500\/28)\n\u200b\t\n \u00d73)\n=\n105044.98"
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