1100×4=4400
P(1+r)n
4000(1+r)4=4400
(1+r)4=1.1
1+r=1.02411
r=0.02411=2.411%
The compound intrests that makes a more expensive should be >2.411%
b.The future cost of this amount is
1000+(3×1100)=4300
Pv of a future sum =
(1+r)nFv
(1+1002.411)44300
=3909.0923 c .Its true that option 3 is cheaper than option 2
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