"1100\u00d74=4400"
"P(1+r)^n"
"4000(1+r)^4=4400"
"(1+r)^4=1.1"
"1+r=1.02411"
"r=0.02411=2.411\\%"
The compound intrests that makes a more expensive should be >2.411%
b.The future cost of this amount is
"1000+(3\u00d71100)=4300"
Pv of a future sum =
"4300\\over(1+{2.411\\over100})^4"
"=3909.0923"
c .Its true that option 3 is cheaper than option 2
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