Question #119232
I. Find the present and future value of $1000 received every month end for 20 years if the interest rate is J12 = 12% p.a. II. Find the present value of $10,000 received at the start of every year for 20 years if the interest rate is J1 = 12% p.a. and if the first payment of $10,000 is received at the end of 10 years. III. John is currently 25 years old. He has $10,000 saved up and wishes to deposit this into a savings account which pays him J12 = 6% p.a. He also wishes to deposit $X every month into that account so that when he retires at 55, he can withdraw $2000 every month end to support his retirement. He expects to live up till 70 years. How much should he deposit every month into his account?
1
Expert's answer
2020-06-02T17:39:58-0400

I)

im=1.12112=1.0095im=1.12^{\frac{1}{12}}=1.0095

im- rate in month

FV=10001.009524011.00951=912,845.15FV=1000*\frac{1.0095^{240}-1}{1.0095-1}=912,845.15

FV-future value

PV=1000(11.0095)240111.00951=95,282.58PV=1000*\frac{(\frac{1}{1.0095})^{240}-1}{\frac{1}{1.0095}-1}=95,282.58

PV-present value

II) PV=10,000(11.12)30111.121(11.12)10111.121=26,971.52PV=10,000*\frac{(\frac{1}{1.12})^{30}-1}{\frac{1}{1.12}-1}-\frac{(\frac{1}{1.12})^{10}-1}{\frac{1}{1.12}-1}=26,971.52

III)5570=15 years55-70=15\ years

2,0001.064511.0611.063011.061=267,370.652,000*\frac{1.06^{45}-1}{1.06-1}-\frac{1.06^{30}-1}{1.06-1}=267,370.65

267,370.6510,0001.0630=209,936.14267,370.65-10,000*1.06^{30}=209,936.14

209,936.14=x1.063011.061209,936.14=x*\frac{1.06^{30}-1}{1.06-1}

x=2,655.47x=2,655.47


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS