Let the rate of interest be r % per annum.
A=P(1+r2×100)2nA=P(1+\frac r{2\times100})^{2n}A=P(1+2×100r)2n
10000=1000(1+r200)1210000=1000(1+\frac r{200})^{12}10000=1000(1+200r)12
1+r200=1+\frac{r}{200}=1+200r= 101/12≈1.21110^{1/12}\approx 1.211101/12≈1.211
r≈\approx≈ 42%.
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