"A=P(1+\\frac{r}{100})^n"
here A is the amount after n intervals P is the principal amount r is the interest rate and n is the number of intervals
here number of years is 18-5=13 but as the rate is applied semiannualy so n =2x13 =26
let's substitute in the formula
"130000=P(1+\\frac{3}{200})^{26}\\\\130000=P(1.4727)\\\\P=\\frac{130000}{1.4727}=\\$88273.24"
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