A=P(1+100r)n
here A is the amount after n intervals P is the principal amount r is the interest rate and n is the number of intervals
here number of years is 18-5=13 but as the rate is applied semiannualy so n =2x13 =26
let's substitute in the formula
130000=P(1+2003)26130000=P(1.4727)P=1.4727130000=$88273.24
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