Question #107411
5,100 dollars invested for 10 years at 9 percent compounded annually is?
1
Expert's answer
2020-04-01T14:54:33-0400

We need to find the compound interest.

Given,


P=$5100t=10 yearsr=9%=0.09compounded Annually,so n=1P = \$5100 \\ t= 10 \space years \\ r=9\% = 0.09 \\ compounded \space Annually, so \space n = 1

Formula to find the compound interest =AmountPrincipal= Amount - Principal

=P(1+rn)ntP= P (1 + \frac{r}{n})^{nt} - P



=5100(1+0.091)10×15100=5100(1.09)105100= 5100 ( 1+ \frac{0.09}{1})^{10 \times 1} -5100 = 5100 (1.09)^{10} - 5100

=5100×2.36735100=12073.235100=6973.23= 5100 \times 2.3673 - 5100 = 12073.23 - 5100 = 6973.23\\

Amount=compoundinterest+PrincipalAmount=compound\, interest+Principal

Answer:

The compounded interest = $6973.23\$ 6973.23

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