(P∪Q)=(1,2,3,4,6,9,10), (P∪Q)′=(5,7,8).(P\cup Q)=(1,2,3,4,6,9,10),\;\;(P\cup Q)'=(5,7,8).(P∪Q)=(1,2,3,4,6,9,10),(P∪Q)′=(5,7,8).
P′=(3,5,7,8,9), Q′=(1,4,5,7,8,10), P′∩Q′=(5,7,8).P'=(3,5,7,8,9),\;\;Q'=(1,4,5,7,8,10),\;\;P'\cap Q'=(5,7,8).P′=(3,5,7,8,9),Q′=(1,4,5,7,8,10),P′∩Q′=(5,7,8).
So, (P∪Q)′=P′∩Q′.So,\;\;(P\cup Q)'=P'\cap Q'.So,(P∪Q)′=P′∩Q′.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments