Question #87692

Let A = {1, 2, 3, 4} and let R be a relation on A such that R = {(1, 1),(2, 2),(3, 3),(4, 4),(1, 2),(2, 3),(3, 2),(2, 1)}

Is R transitive? Symmetric? Reflexive?
1

Expert's answer

2019-04-08T13:55:08-0400

Answer to Question #87692 – Math – Discrete Mathematics

Question

Let A={1,2,3,4}A = \{1, 2, 3, 4\} and let RR be a relation on AA such that R={(1,1),(2,2),(3,3),(4,4),(1,2),(2,3),(3,2),(2,1)}R = \{(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (2, 3), (3, 2), (2, 1)\}. Is RR Transitive? Symmetric? Reflexive?

Solution

A relation RR is **reflexive** if (a,a)R(a, a) \in R, for all aAa \in A.

(1,1),(2,2),(3,3),(4,4)R(1, 1), (2, 2), (3, 3), (4, 4) \in R. Hence RR is reflexive.

A relation RR is **symmetric** if (a,b)R(a, b) \in R, then (b,a)R(b, a) \in R, for a,bAa, b \in A.

(1,2)R,(2,1)R(1, 2) \in R, (2, 1) \in R.

(2,3)R,(3,3)R(2, 3) \in R, (3, 3) \in R.

Thus RR is symmetric.

A relation RR is **transitive** if (a,b)R(a, b) \in R, (b,c)R(b, c) \in R, then (a,c)R(a, c) \in R, for all a,b,cAa, b, c \in A.

(1,2)R(1, 2) \in R and (2,3)R(2, 3) \in R, but (1,3)R(1, 3) \notin R.

Thus, RR is not transitive.

**Answer**: it is not transitive, it is symmetric, it is reflexive.

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