Question #85964

Recall that a real number x is rational if x = p/q for integers p, q with q = ̸= 0.

Prove that if x is rational then 1/(2x+1) is rational. Then prove that if 1/(2x+1) is rational then x is rational.

Expert's answer

Answer on Question #85964 – Math – Discrete Mathematics

Question

Recall that a real number xx is rational if x=p/qx = p/q for integers p,qp, q with q0q \neq 0.

Prove that if xx is rational then 1/(2x+1)1/(2x + 1) is rational. Then prove that if 1/(2x+1)1/(2x + 1) is rational then xx is rational.

Solution

1) If xx is rational then x=pqx = \frac{p}{q}, where pp and qq are integers with q0q \neq 0.

So 12x+1=12pq+1=12p+qq=q2p+q\frac{1}{2x + 1} = \frac{1}{2^{\frac{p}{q}} + 1} = \frac{\frac{1}{2p + q}}{q} = \frac{q}{2p + q}. Since qq and 2p+q2p + q are integers with 2p+q02p + q \neq 0, then q2p+q=12x+1\frac{q}{2p + q} = \frac{1}{2x + 1} is rational.

2) If 12x+1\frac{1}{2x + 1} is rational then 12x+1=pq\frac{1}{2x + 1} = \frac{p}{q}, where pp and qq are integers with q0q \neq 0.

In addition, p=q12x+10p = q * \frac{1}{2x + 1} \neq 0. Therefore 2x+1=qp2x + 1 = \frac{q}{p}, and 2x=qp1=qpp2x = \frac{q}{p} - 1 = \frac{q - p}{p}. So x=qp2px = \frac{q - p}{2p}.

Since qpq - p and 2p2p are integers with 2p02p \neq 0, then qp2p=x\frac{q - p}{2p} = x is rational.

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