Question #83062

determine that wheter the functions from real numbers to real numbers are one to one
f(n)=n^3
f(n)=n^2+1

Expert's answer

Answer on Question #83062 – Math – Discrete Mathematics

Question

determine that whether the functions from real numbers to real numbers are one to one

f(n)=n^3

f(n)=n^2+1

Solution

If the statement f(a)=f(b)f(a) = f(b) implies a=ba = b, then the function f(x)f(x) is one to one.

We apply this test to check the function f(n)=n3f(n) = n^3:


a3=b3a^3 = b^3a=ba = b


Therefore f(n)=n3f(n) = n^3 is one to one.

We apply this test to check the function f(n)=n2+1f(n) = n^2 + 1:


a2+1=b2+1a^2 + 1 = b^2 + 1a2=b2a^2 = b^2a=bora=ba = b \quad \text{or} \quad a = -b


Therefore f(n)=n2+1f(n) = n^2 + 1 is not one to one.

Answer:

f(n)=n3f(n) = n^3 is one to one.

f(n)=n2+1f(n) = n^2 + 1 is not one to one.

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