Question #76365

Let X = {0, 1, 2}. Consider the power set P(X). Recall that P(X) = {A such that A ⊆ X}.
Determine if each statement is true or false. (a) X ∈ P(X).
(b) ∅∈P(X)
(c) X ⊆ P(X).
(d) {0,2}∈P(X) (e) {0,2,1} ∈ X (f) {0}⊆X
(g) {{0}} ⊆ P(X)

Expert's answer

Answer on Question #76365 – Math – Discrete Mathematics

Question

Let X={0,1,2}X = \{0,1,2\}. Consider the power set P(X)P(X). Recall that P(X)={A such that AX}P(X) = \{A \text{ such that } A \subseteq X\}. Determine, if each statement is true or false.

(a) XP(X)X \in P(X);

(b) P(X)\varnothing \in P(X);

(c) XP(X)X \subseteq P(X);

(d) {0,2}P(X)\{0,2\} \in P(X);

(e) {0,2,1}X\{0,2,1\} \in X;

(f) {0}X\{0\} \subseteq X;

(g) {{0}}P(X)\{\{0\}\} \subseteq P(X).

Solution

(a). Since XXX \subseteq X for the set XX, then XP(X)X \in P(X) by definition of P(X)P(X).

Answer: The statement is true.

(b). Since X\varnothing \subseteq X for XX, then XP(X)X \in P(X) by definition of P(X)P(X).

Answer: The statement is true.

(c). The set P(X)P(X) consists of all subsets of XX. Consequently, every subset of XX lies in P(X)P(X) as an element, but not as a subset. Therefore the statement XP(X)X \subseteq P(X) is not true.

Answer: The statement is false.

(d). Since {0,2}X\{0,2\} \subseteq X, then {0,2}P(X)\{0,2\} \in P(X).

Answer: The statement is true.

(e). The set XX consists of elements 0,1,20, 1, 2 only. Consequently, {2,0,1}X\{2, 0, 1\} \notin X.

Answer: The statement is false.

(f). Since 0X0 \in X, then the set {0}\{0\} (which consists of only \emptyset) is a subset of XX, i.e. {0}X\{0\} \subseteq X.

Answer: The statement is true.

(g). Since {0}P(X)\{0\} \in P(X), then the set {{0}}\{\{0\}\} (which consist of only {0}\{0\} element of P(X)P(X)) is a subset of P(X)P(X), i.e. {{0}}P(X)\{\{0\}\} \subseteq P(X).

Answer: The statement is true.

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