Answer on Question #76238 – Math – Discrete Mathematics.
Question
Let X={1,2,3}. Define a relation ∼ on P(X) by A∼B if A and B have the same number of elements.
Prove that ∼ is an equivalence relation. Write down all equivalence classes of ∼.
Solution
**Reflexively:** Let A∈P(x). Then A∼A because the set has an unaltered number of elements.
**Symmetric:** Let A∈P(x), B∈P(x) and A∼B. Since A∼B, ∣A∣=∣B∣. Then ∣B∣=∣A∣. Since ∣B∣=∣A∣, B∼A.
**Transitivity:** Let A∈P(x), B∈P(x), C∈P(x), A∼B and B∼C. Since A∼B, ∣A∣=∣B∣. Since B∼C, ∣B∣=∣C∣. Then ∣A∣=∣C∣ because ∣A∣=∣B∣ and ∣B∣=∣C∣. Since ∣A∣=∣C∣, A∼C.
Equivalence classes of ∼:
[∅]={∅} (zero of elements),[{1}]={{1},{2},{3}} (one element),[{1,2}]={{1,2},{1,3},{2,3}} (two elements),[{1,2,3}]={{1,2,3}} (three elements).
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