Question #75939

Prove that A ∩ B = A ∪ B.

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Answer on Question #75939 – Math – Discrete Mathematics

Question

Prove that AB=ABA \cap B = A \cup B.

Solution

AB={xxA or xB}A \cup B = \{x \mid x \in A \text{ or } x \in B\}AB={xxA and xB}A \cap B = \{x \mid x \in A \text{ and } x \in B\}


Let's show, that the equality AB=ABA \cup B = A \cap B is not always true, that is, we show that A\exists A and B:ABABB: A \cup B \neq A \cap B.

For example, A={1,2,3},B={3,4,5}A = \{1,2,3\}, B = \{3,4,5\}.

Then AB={1,2,3,4,5}A \cup B = \{1,2,3,4,5\} and AB={3}A \cap B = \{3\}. Therefore ABABA \cup B \neq A \cap B.

Nevertheless, the equality AB=ABA \cup B = A \cap B may be true (for example, if A=BA = B).

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