Answer on Question #75727 – Math – Discrete Mathematics
Firstly, there are (35)=10 different ways of choosing three people to sit at the table. Once we pick three people A, B and C to sit at the table. There are
ways to rotate the tableways to sit three people in a row=number of chairsways to sit three people in a row=33!=2,
ways to sit 3 people at a circular table. Hence, there are
10×2=20
3-permutations of 5 people.
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