Question #74549

An integer solution to the equation 3x+4=7y is an ordered pair of integers (x, y) that satisfies the equation. For example, (1,1) is one such solution. Write the set of all integer solutions to the equation 3x + 4 = 7y in set builder notation.
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Expert's answer

2018-03-14T09:49:07-0400

Answer on Question #74549 – Math – Discrete Mathematics

Question

An integer solution to the equation 3x+4=7y3x + 4 = 7y is an ordered pair of integers (x,y)(x, y) that satisfies the equation. For example, (1,1)(1, 1) is one such solution. Write the set of all integer solutions to the equation 3x+4=7y3x + 4 = 7y in set builder notation.

Solution

3x+4=7y3x + 4 = 7y3x=7y43x = 7y - 4


Residue method

The left and the right side of the equation are divided into 3 groups.

if y=3m,mZy = 3m, m \in \mathbb{Z} then 7y4=7(3m)4=21m4(21m4)mod307y - 4 = 7(3m) - 4 = 21m - 4 \quad (21m - 4) \mod 3 \neq 0

if y=3m+1,mZy = 3m + 1, m \in \mathbb{Z} then 7y4=7(3m+1)4=21m+3(21m+3)mod3=07y - 4 = 7(3m + 1) - 4 = 21m + 3 \quad (21m + 3) \mod 3 = 0

if y=3m+2,mZy = 3m + 2, m \in \mathbb{Z} then 7y4=7(3m+2)4=21m+10(21m+10)mod307y - 4 = 7(3m + 2) - 4 = 21m + 10 \quad (21m + 10) \mod 3 \neq 0

y=3m+1,mZy = 3m + 1, \quad m \in \mathbb{Z}3x=7y4=7(3m+1)4=21m+33x = 7y - 4 = 7(3m + 1) - 4 = 21m + 3x=7m+1x = 7m + 1


Answer:


{(x;y)x=1+7m,y=1+3m,mZ}\{(x; y) \mid x = 1 + 7m, y = 1 + 3m, m \in \mathbb{Z}\}


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