Answer on Question #62450 – Math – Discrete Mathematics
Question
Given:
M={31,21,53,32,75,…}
Write: in the set builder form
Solution
The problem has more than one solution.
Example 1.
We have to reduce to a common denominator all fractions
So d=5⋅7⋅3⋅2=30⋅7=210
Then:
31=2107021=21010553=21012632=21014075=210150
So we obtain
31<21<53<32<75.
We can see that the difference between the denominator and the numerator for numbers at the odd position is 2.
We can see that the difference between the denominator and the numerator for numbers at the even position is 1.
In the set builder form
M={2n+12n−1,n+1n:n=1,2,3,…}.
Answer: In the set builder form
M={2n+12n−1,n+1n:n=1,2,3,…}.Example 2.
3121=425332=6475
We can see that in all cases the difference between the denominator and the numerator is 2.
In the set builder form
M={n+2n:n=1,2,3,…}.
Answer: In the set builder form
M={n+2n:n=1,2,3,…}.
www.AssignmentExpert.com