Without using truth table prove that (p→q)ᴧ(q→r)→(p→r) is a tautology
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Expert's answer
2014-12-29T02:30:45-0500
To make it false The right side must be false, so (p = T, r = F). To make the lift side true, so p q must be true since (p=t)so (q =t) and q r must be true, since (r=f) so (q = f). So we cannot make it false so it is a tautology.
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