Question #43450

write the following boolean expressions in an equivalent sum of product canonical form in three variables x1, x2, and x3:
1. x1*x2 ?
2. x1⊕x2 ?
3. (x1⊗X2)'*X3

Expert's answer

Answer on Question #43450, Math, Discrete Mathematics

write the following boolean expressions in an equivalent sum of product canonical form in three variables x1, x2, and x3:

1. x1*x2 ?

2. x1 ⊕ x2 ?

3. (x1 ⊗ X2) * X3

Solution.

We will express each function as sum of minterms.

1. f(x1,x2,x3)=x1x2=x1x2(x3+x3)=x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = x_{1}x_{2} = x_{1}x_{2}(x_{3} + x_{3}') = x_{1}x_{2}x_{3} + x_{1}x_{2}x_{3}.

2. f(x1,x2,x3)=x1x2=x1x2+x1x2=x1x2(x3+x3)+x1x2(x3+x3)=x1x2x3+x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = x_{1}\oplus x_{2} = x_{1}^{\prime}x_{2} + x_{1}^{\prime}x_{2} = x_{1}^{\prime}x_{2}(x_{3} + x_{3}^{\prime}) + x_{1}^{\prime}x_{2}(x_{3} + x_{3}^{\prime}) = x_{1}^{\prime}x_{2}x_{3} + x_{1}^{\prime}x_{2}x_{3}^{\prime} + x_{1}^{\prime}x_{2}x_{3}^{\prime}.

3. f(x1,x2,x3)=(x1x2)x3=(x1x2+x1x2)x3=(x1+x2)(x1+x2)x3=x1x1x3+x1x2x3+x1x2x3+x2x2x3=x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = (x_{1}\oplus x_{2})^{\prime}x_{3} = (x_{1}^{\prime}x_{2} + x_{1}^{\prime}x_{2})^{\prime}x_{3} = (x_{1} + x_{2}^{\prime})(x_{1}^{\prime} + x_{2})x_{3} = x_{1}x_{1}^{\prime}x_{3} + x_{1}x_{2}x_{3} + x_{1}^{\prime}x_{2}^{\prime}x_{3} + x_{2}x_{2}^{\prime}x_{3} = x_{1}x_{2}x_{3} + x_{1}^{\prime}x_{2}^{\prime}x_{3}.

Answer:

1. f(x1,x2,x3)=x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = x_{1}x_{2}x_{3} + x_{1}x_{2}x_{3}.

2. f(x1,x2,x3)=x1x2x3+x1x2x3+x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = x_{1}^{\prime}x_{2}x_{3} + x_{1}^{\prime}x_{2}x_{3}^{\prime} + x_{1}^{\prime}x_{2}x_{3} + x_{1}^{\prime}x_{2}x_{3}^{\prime}.

3. f(x1,x2,x3)=x1x2x3+x1x2x3f(x_{1},x_{2},x_{3}) = x_{1}x_{2}x_{3} + x_{1}^{\prime}x_{2}^{\prime}x_{3}.

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