Question #350642

Patrick has assignments in 5 subjects. He can only do two assignments . In how many ways can do two assignments?

1
Expert's answer
2022-06-15T05:47:13-0400

We use the formula of combinations Ckn=n!k!(nk)!C_k^n=\frac{n!}{k!(n-k)!}, n>kn>k.

We have 55 subjects, so n=5n=5.

Patrick can only do two assigments, so k=2k=2.


Number of ways can do two assignments equals C25=5!2!(52)!=5!2!3!=5432121321=52=10C_2^5=\frac{5!}{2!(5-2)!}=\frac{5!}{2!3!}=\frac{5\cdot4\cdot3\cdot2\cdot1}{2\cdot1\cdot3\cdot2\cdot1}=5\cdot2=10.


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