Find the sum-of-products expansions of these boolean functions: F(x,y,z) = x.
We should create the table for the function and take the Boolean sum of the minterm where the function evaluates to 1.
F(x,y,z)=xF(x,y,z)=xF(x,y,z)=x
So, the disjunctive normal form is xyˉzˉ+xyˉz+xyzˉ+xyzx\=y\=z+x\=yz+xy\=z+xyzxyˉzˉ+xyˉz+xyzˉ+xyz
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