Answer to Question #341224 in Discrete Mathematics for Bunny

Question #341224

Read the instruction carefully .

Consider the Function f={1,2,3,4}->{1,2,3,4} given by f(n) =(1 2 3 4) (4 1 3 4)

a.find f(1)=

b.Find an element n in the domain such that f(n)=1

c.Find an element n of the domain such that f(n)=n

d.Find an element of the domain that is not range.=


The following functions all have {1,2,3,4,5} as both domain and codomain for each.determine whether it is (only) injective,(only) surjective, bijective or either injective nor surjective.

a. f=(1 2 3 4 5) (3 3 3 3 3)=

b.f=(1 2 3 4 5) (2 3 1 5 4)=

c.f(x)=6-x =

d. f(x)={x/2

(x+1)/2

if x is even

if x is odd=


The following function all have domain {1 2 3 4 5} and co domain { 1 2 3}. For each determine whether it is (only)injective,(only) surjective, bijective or either injective nor surjective.


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