Answer to Question #338194 in Discrete Mathematics for Agg

Question #338194

U={1,2,3,4,5,6,7,8,9,10}



A={2,3,4,5,8}



B={2,4,6,8,10}



C={1,3,5,7,9}




Instruction: Solve the given below using the sets above



1.( (C U A)-B)’ ∩ (B’ U A)



2.(((BUA)’ U (CUA)’) U ((A-B)’ ∩ (B-C)’))

1
Expert's answer
2022-05-09T11:12:43-0400

2.(BUA)={2,3,4,5,6,8,10}(BUA)={1,7,9}2.(BUA)=\{2,3,4,5,6,8,10\}\\(BUA)'=\{1,7,9\}

(CUA)={1,2,3,4,5,7,8,9}(CUA)={6,10}(CUA)=\{1,2,3,4,5,7,8,9\}\\(CUA)'=\{6,10\}

((BUA)U(CUA))={1,6,7,9,10}((BUA)’ U (CUA)’)=\{1,6,7,9,10\}

AB={3,5}A-B=\{3,5\}

(AB)={1,2,4,6,7,8,9,10}(A-B)'=\{1,2,4,6,7,8,9,10\}

BC={2,4,6,8,10}B-C=\{2,4,6,8,10\}

(BC)={1,3,5,7,9}(B-C)'=\{1,3,5,7,9\}

(AB)(BC)={1,7,9}(A-B)' \cap(B-C)'=\{1,7,9\}

(((BUA)U(CUA))U((AB)(BC)))={1,6,7,9,10}(((BUA)’ U (CUA)’) U ((A-B)’ ∩ (B-C)’))=\{1,6,7,9,10\}

1. (CUA)={1,2,3,4,5,7,8,9}(CUA)=\{1,2,3,4,5,7,8,9\}

(CUA)B={1,3,5,7,9}(CUA)-B=\{1,3,5,7,9\}

((CUA)B)={2,4,6,8,10}((CUA)-B)'=\{2,4,6,8,10\}

B={1,3,5,7,9}B'=\{1,3,5,7,9\}

BUA={1,2,3,4,5,7,8,9}B' U A=\{1,2,3,4,5,7,8,9\}

((CUA)B)(BUA)={2,4,8}( (C U A)-B)’ ∩ (B’ U A)=\{2,4,8\}


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