Consider two cases:
- Suppose that y is odd. It means, that we can present y as: y=2n+1, where n∈Z. We get: 9(2n+1)2+3(2n+1)−2=9(4n2+4n+1)+6n+1=36n2+42n+10. The latter number is even
- Suppose that y is even. It means that we can present y as: y=2n. We receive: 36n2+6n−2. The latter number is even.
Thus, we have shown that the number 9y2+3y−2 is even.
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