Question

Find the inverse of the given function. Upload solution in next number.

Let f:R→R , f(x)= 4x + 3

a. f^-1 (y)= 

b. f^-1 (35) = 

c. f^-1 (-9) = 

Answer 1

• $Let f ^{ −1} (x)=y ⇒ x=f(y) ⇒ x=4y+3 ⇒ x−3=4y ⇒ y= \frac{ x−3 ​}{4}$

b.$f^{-1}(35)=\frac{35-3}{4}=8$

c. $f^{-1}(-9)=\frac{-9-3}{4}=-3$