Question #325618

Number plates in an Arab country consist of 3 letters (chosen from a specified set of 20 letters from the Arabic alphabet) and 4 digits (from 0 to 9).

⦁ Find the probability of a plate having identical letters.

⦁ Find the probability of a plate having identical digits.

⦁ Find the probability of a plate having consecutive digits.


Expert's answer

1:20⋅120⋅120⋅120=0.00252:10⋅110⋅110⋅110⋅110=0.0013:The  4digits  in  ascending  order  can  start  from  0,1,2,3,4,5That  is  6waysThere  are  2ways  to  choose  order  (ascending  or  descending)Total  6⋅2=12ways  of  104=10000variants  of  digitsThe  probability  is1210000=0.00121:\\20\cdot \frac{1}{20}\cdot \frac{1}{20}\cdot \frac{1}{20}=0.0025\\2:\\10\cdot \frac{1}{10}\cdot \frac{1}{10}\cdot \frac{1}{10}\cdot \frac{1}{10}=0.001\\3:\\The\,\,4 digits\,\,in\,\,ascending\,\,order\,\,can\,\,start\,\,from\,\,0,1,2,3,4,5\\That\,\,is\,\,6 ways\\There\,\,are\,\,2 ways\,\,to\,\,choose\,\,order\,\,\left( ascending\,\,or\,\,descending \right) \\Total\,\,6\cdot 2=12 ways\,\,of\,\,10^4=10000 variants\,\,of\,\,digits\\The\,\,probability\,\,is\\\frac{12}{10000}=0.0012


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