Find out if the following functions are one-to-one and/or onto. a. š: š ā š , š(š„) = š„ 3 + 1 b. š: š + ā š +, š(š„) = |š„| + 5
a:fāoneātoāone:f(x)=f(y)āx3+1=y3+1āx=yfānotāāonto:f(x)=3āx3+1=3āx3=2āxāZb:fāoneātoāone:f(x)=f(y)āā£xā£+5=ā£yā£+5āā£xā£=ā£yā£ā[x,yāR+]āx=yfānotāāonto:f(x)=1āx+5=1āx=ā4āxāR+a:\\f-one-to-one:\\f\left( x \right) =f\left( y \right) \Rightarrow x^3+1=y^3+1\Rightarrow x=y\\f-not\,\,onto:\\f\left( x \right) =3\Rightarrow x^3+1=3\Rightarrow x^3=2\Rightarrow x\notin \mathbb{Z} \\b:\\f-one-to-one:\\f\left( x \right) =f\left( y \right) \Rightarrow \left| x \right|+5=\left| y \right|+5\Rightarrow \left| x \right|=\left| y \right|\Rightarrow \left[ x,y\in \mathbb{R} _+ \right] \Rightarrow x=y\\f-not\,\,onto:\\f\left( x \right) =1\Rightarrow x+5=1\Rightarrow x=-4\Rightarrow x\notin \mathbb{R} _+a:fāoneātoāone:f(x)=f(y)āx3+1=y3+1āx=yfānotonto:f(x)=3āx3+1=3āx3=2āxā/Zb:fāoneātoāone:f(x)=f(y)āā£xā£+5=ā£yā£+5āā£xā£=ā£yā£ā[x,yāR+ā]āx=yfānotonto:f(x)=1āx+5=1āx=ā4āxā/R+ā
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