Let π(π₯) = 2π₯2β3π₯+7 / 5x2-2x. Find π(3).
f(3)=2β 32β3β 3+75β 32β2β 3==1639=0.41.f(3)=\cfrac{2\cdot3^2-3\cdot3+7}{5\cdot3^2-2\cdot3}=\\ =\cfrac{16}{39}=0.41.f(3)=5β 32β2β 32β 32β3β 3+7β==3916β=0.41.
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