Question #323400

Let π‘“(π‘₯) = 2π‘₯2βˆ’3π‘₯+7 / 5x2-2x. Find π‘“(3).


1
Expert's answer
2022-04-05T06:57:29-0400

f(3)=2β‹…32βˆ’3β‹…3+75β‹…32βˆ’2β‹…3==1639=0.41.f(3)=\cfrac{2\cdot3^2-3\cdot3+7}{5\cdot3^2-2\cdot3}=\\ =\cfrac{16}{39}=0.41.


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